Asked by Anonymous
there are a 1000 tickets. Price for children's ticket is 6.5. Adult tickets are 9.5. total tickets sales are 8444. how many adult and children tickets are sold. Using binomials to solve.
x+y = 16 (1 child + 1 Adult = 16)
6.5X + 9.5Y = 8444
6.5(16-y) + 9.5Y = 8444
What am I doing wrong?
x+y = 16 (1 child + 1 Adult = 16)
6.5X + 9.5Y = 8444
6.5(16-y) + 9.5Y = 8444
What am I doing wrong?
Answers
Answered by
Steve
do not mix up the quantity with the prices. We know there are 1000 tickets, so
x+y = 1000
now add up the prices, remembering that x and y are the number of tickets:
6.5x + 9.5y = 8444
you used x,y for prices in one place, number of tickets in the other. Using the two equations I showed above,
6.5x + 9.5(1000-x) = 8444
3x = 1056
x = 352
so, y = 1000-x = 648
x+y = 1000
now add up the prices, remembering that x and y are the number of tickets:
6.5x + 9.5y = 8444
you used x,y for prices in one place, number of tickets in the other. Using the two equations I showed above,
6.5x + 9.5(1000-x) = 8444
3x = 1056
x = 352
so, y = 1000-x = 648
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.