Question
there are a 1000 tickets. Price for children's ticket is 6.5. Adult tickets are 9.5. total tickets sales are 8444. how many adult and children tickets are sold. Using binomials to solve.
x+y = 16 (1 child + 1 Adult = 16)
6.5X + 9.5Y = 8444
6.5(16-y) + 9.5Y = 8444
What am I doing wrong?
x+y = 16 (1 child + 1 Adult = 16)
6.5X + 9.5Y = 8444
6.5(16-y) + 9.5Y = 8444
What am I doing wrong?
Answers
do not mix up the quantity with the prices. We know there are 1000 tickets, so
x+y = 1000
now add up the prices, remembering that x and y are the number of tickets:
6.5x + 9.5y = 8444
you used x,y for prices in one place, number of tickets in the other. Using the two equations I showed above,
6.5x + 9.5(1000-x) = 8444
3x = 1056
x = 352
so, y = 1000-x = 648
x+y = 1000
now add up the prices, remembering that x and y are the number of tickets:
6.5x + 9.5y = 8444
you used x,y for prices in one place, number of tickets in the other. Using the two equations I showed above,
6.5x + 9.5(1000-x) = 8444
3x = 1056
x = 352
so, y = 1000-x = 648
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