Asked by Adam
Suppose you would like to cross a 209-foot wide river in a boat. Assume that the boat can travel 32 mph relative to the water and that the current is flowing west at the rate of 6 mph. If the bearing chosen is chosen so that the boat will land at a point exactly across from its starting loin, how long will it take for the boat to make the crossing? Give your answer to the nearest second.
Answers
Answered by
Steve
if the boat travels s seconds,
1 km/hr = 1.4667 ft/s
209^2 + (6*1.4667s)^2 = (32*1.4667s)^2
s = 4.5 sec
1 km/hr = 1.4667 ft/s
209^2 + (6*1.4667s)^2 = (32*1.4667s)^2
s = 4.5 sec
Answered by
A. J.
1 mile/hr=1.46667 ft/sec. The KM here is a typo. The rest o the problem is good and correct. Giving direction on how to draw a diagram to visualize would have been be great.
Thanks and keep up the good work.
Thanks and keep up the good work.
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