Asked by Danny

A 225-kg crate is pushed horizontally with a force of 690 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.
Answered by Damon
friction force = 225*9.81*.2 = 441 N
690 - 441 = m a = 225 a
a = 1.11 m/s^2
Answered by Giselle
How did you get from 225 to 1.11?
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