Question

Joe wishes to hang a sign weighing 730 N so that cable A, attached to the store, makes a 30.0° angle, as shown below. Cable B is horizontal and attached to an adjoining building. What is the tension in cable B?
T sin 30 = force up = 730
T = 1460 N in cable A
T cos 30 = horizontal component = 1460 cos 30 = 1264 N
thank you and the answer is 433 to anyone else trying to figure this out
The answer is 375 N

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