the temperature of 50.0g of water changes from 28.5°C to 26.9°C when 1.00g of ammonium bromide, NH4br(s), dissolves. What is the molar enthalpy of solution for this compound?

Answer 1

The change of T of water is the way you get to the dH soln.
q = mass H2O x specific heat H2O x (28.5-26.9) = ? in joules if sp.j. in joules.
q/50.0 g = delta H/gram
(delta H/gram) x (molar mass NH4Br) = delta H in J/mol. The usual way of expressing this is in kJ/mol convert J to kJ for this.