Asked by Anonymous
the temperature of 50.0g of water changes from 28.5°C to 26.9°C when 1.00g of ammonium bromide, NH4br(s), dissolves. What is the molar enthalpy of solution for this compound?
Answers
Answered by
DrBob222
The change of T of water is the way you get to the dH soln.
q = mass H2O x specific heat H2O x (28.5-26.9) = ? in joules if sp.j. in joules.
q/50.0 g = delta H/gram
(delta H/gram) x (molar mass NH4Br) = delta H in J/mol. The usual way of expressing this is in kJ/mol convert J to kJ for this.
q = mass H2O x specific heat H2O x (28.5-26.9) = ? in joules if sp.j. in joules.
q/50.0 g = delta H/gram
(delta H/gram) x (molar mass NH4Br) = delta H in J/mol. The usual way of expressing this is in kJ/mol convert J to kJ for this.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.