Asked by Nikki
A 0.08425 g sample of gas occupies 10.0-mL at 292.5 K and 1.10 atm. Upon further analysis, the compound is found to be 13.068% C and 86.932% Br. What is the molecular formula of the compound?
Identify the geometry around each carbon atom. a)trigonal pyramidal b)bent c)tetrahedral d)linear e)trigonal planar Is the compound polar or nonpolar?
Identify the geometry around each carbon atom. a)trigonal pyramidal b)bent c)tetrahedral d)linear e)trigonal planar Is the compound polar or nonpolar?
Answers
Answered by
DrBob222
Use PV = nRT to solve for n = number of mols. Then n = grams/molar mass. You know grams and n, solve for molar mass.
Take 100 g sample which gives
13.068 g C
86.932 g Br.
Convert grams to mols
mols C = 13.068/atomic mass C.
mols Br = 86.932/atomic mass Br.
Find the ratio of C to Br with the smaller value being 1.00. The easy to do this is to divide the smaller value by itself; divide the other number by the same small number to find empirical formula which will be CxBry.
empirical mass x z = molar mass(from above)
Solve for x which becomes
(empirical formula)x = molecular formula.
Post your work if you get stuck.
Take 100 g sample which gives
13.068 g C
86.932 g Br.
Convert grams to mols
mols C = 13.068/atomic mass C.
mols Br = 86.932/atomic mass Br.
Find the ratio of C to Br with the smaller value being 1.00. The easy to do this is to divide the smaller value by itself; divide the other number by the same small number to find empirical formula which will be CxBry.
empirical mass x z = molar mass(from above)
Solve for x which becomes
(empirical formula)x = molecular formula.
Post your work if you get stuck.
Answered by
Bob
Br7C
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