Asked by daniel
Find the equation of the line that passes through the points (2/3, -5/4)and (-3, -5/6). Write the answer in slope-intercept form and standard form with integer coefficients.
Thank you.
Thank you.
Answers
Answered by
Steve
(y+5/4)/(x-2/3) = (-5/6 + 5/4)/(-3 - 2/3)
3(4y+5) / 4(3x-2) = 5/12 / -11/3 = -5/44
3(4y+5) = -5/44 * 4(3x-2)
12y + 15 = -5/11 * (3x-2)
12y = -15/11 x + 10/11 - 15
12y = -15/11 x - 155/11
y = -5/44 x - 155/132
clear fractions and rearrange for standard form
3(4y+5) / 4(3x-2) = 5/12 / -11/3 = -5/44
3(4y+5) = -5/44 * 4(3x-2)
12y + 15 = -5/11 * (3x-2)
12y = -15/11 x + 10/11 - 15
12y = -15/11 x - 155/11
y = -5/44 x - 155/132
clear fractions and rearrange for standard form
Answered by
Anonymous
What is 475.189 rounded to the nearest hundredth?
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