Asked by Jan
A common laboratory reaction is the neutralization of an acid with a base. When 50.0 mL of the .500 M HCl at 25 C is assed to 50 mL of .500 M NaOH at 25 C in a coffee cup calorimeter, the temperature of the mixture rises to 28.2 C. What is the heat of reaction per mole of acid? Assume the mixture has a specific heat capacity of 4.18 J/gK and that the densities of the reactant solutions are both 1.00 g/mL
Answers
Answered by
DrBob222
q = heat released = [mass H2O x secific heat H2O x (Tfinal-Tinitial)]
mols of rxn = 0.5M x 0.050 L = 0.025 mols.
q/0.025 = delta H in J/mol. Usually this is quoted in kJ/mol so divide by 1000 for kJ/mol.
mols of rxn = 0.5M x 0.050 L = 0.025 mols.
q/0.025 = delta H in J/mol. Usually this is quoted in kJ/mol so divide by 1000 for kJ/mol.
Answered by
abood
912
Answered by
Anonymous
670J
Answered by
Anonymous
1339J
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.