Asked by michelle
Three masses are arranged in the (x, y)
plane.
3kg (0,0)
7kg (10,0)
6kg (0,3)
What is the magnitude of the resulting
force on the 3 kg mass at the origin? The value of the universal gravitational constant is 6.6726 × 10^−11 N · m^2/kg^2.
Answer in units of N
what ive done
G*(7)*(3)/10^2 = 1.401246*10^-11
G*(3)*(6)/3^2 = 1.33452*10^-10
sqrt((1.401246*10^-11)^2 + (1.33452*10^-10)^2)
= 1.341856376*10^-10
my program tells me im wrong. im getting frustrated. please help?
plane.
3kg (0,0)
7kg (10,0)
6kg (0,3)
What is the magnitude of the resulting
force on the 3 kg mass at the origin? The value of the universal gravitational constant is 6.6726 × 10^−11 N · m^2/kg^2.
Answer in units of N
what ive done
G*(7)*(3)/10^2 = 1.401246*10^-11
G*(3)*(6)/3^2 = 1.33452*10^-10
sqrt((1.401246*10^-11)^2 + (1.33452*10^-10)^2)
= 1.341856376*10^-10
my program tells me im wrong. im getting frustrated. please help?
Answers
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.