Question

Find the first five terms of the sequence for which a1=5,and an+1=3an+1.

an+1=3an+1
a1+1=3a1+1
a2=3(5)+1
a2=16

a2+1=3a2+1
a3=3(16)+1
a3=49

a3+1=3a3+1
a4=3(49)+1
a4=148

a4+1=3a4+1
a5=3(148)+1
a5=445

so the first five terms are: 5,16,49,148,445

Answer 1

Your answer is correct, but I am having difficulty following your notation.

How about instead of an+1=3an+1 something like
term(n+1) = 3term(n) + 1