Asked by Rebekah
1. find without a calc
log base 5 of cubed root of 25. I got x=(2/3)
2. ln base e of 3
I got 3
3. find the domain of y= log base 3 of (x/x-1)
I got (negative infinity, 0)union (1, infinity)
4. y= (1/ln x) find the domain
i got ( negative infinity, 1) but im pretty sure that's wrong.
thanks
log base 5 of cubed root of 25. I got x=(2/3)
2. ln base e of 3
I got 3
3. find the domain of y= log base 3 of (x/x-1)
I got (negative infinity, 0)union (1, infinity)
4. y= (1/ln x) find the domain
i got ( negative infinity, 1) but im pretty sure that's wrong.
thanks
Answers
Answered by
Reiny
1.
2/3 is correct
2. ln 3 cannot be found without a calculator.
ln 3 = appr 1.0986
3. This is a bit tricky.
I know that if x = -5, then we get
log<sub>3</sub>(-5/-6)
= log<sub>3</sub> (5/6) which is defined
BUT, since
log<sub>3</sub>(x/(x-1))
= log x - log(x-1)
from that simplification x>1
4. yes, you are wrong
y = 1/lnx , remember we can only take logs of positive numbers,
so x > 0
2/3 is correct
2. ln 3 cannot be found without a calculator.
ln 3 = appr 1.0986
3. This is a bit tricky.
I know that if x = -5, then we get
log<sub>3</sub>(-5/-6)
= log<sub>3</sub> (5/6) which is defined
BUT, since
log<sub>3</sub>(x/(x-1))
= log x - log(x-1)
from that simplification x>1
4. yes, you are wrong
y = 1/lnx , remember we can only take logs of positive numbers,
so x > 0
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