Asked by Jon
Find the sum of a geometric series for which a1=1,r=2,and n=6.
Sn=a1(1-r^n)/1-r
S6=1(1-2^6)/1-2
S6=1(1-64)/1-2
S6=63/1
63 (answer)
Sn=a1(1-r^n)/1-r
S6=1(1-2^6)/1-2
S6=1(1-64)/1-2
S6=63/1
63 (answer)
Answers
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Reiny
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