critical values are values in the domain where f'(x) = 0
since f'(x) = 3x^2 + 6x - 1, the critical values would be (-3±2√3)/2
the extrema occur at the critical values.
let f(x)=x^3+3x^2-2x+4
What are the critical values?
Where are the relative extrema, if they exist?
2 answers
oops. f' = 3x^2 + 6x - 2.
extrema at x=(-3±√15)/3
extrema at x=(-3±√15)/3
0 answers