Asked by chocolateman
A bowl contains only red marbles, blue marbles and green marbles. The probability of selecting a red marble from the bowl is 3/13. The probability of selecting a blue marble from the bowl is 2/5. There are fewer than 100 marbles in the bowl. What is the probability of selecting, at random and without replacement, a green marble and then a red marble from the bowl on the first two selections?
Express your answer as a common fraction.
Express your answer as a common fraction.
Answers
Answered by
PsyDAG
3/13 = .23 for red marble
2/5 = .40 for blue marble
?? for green marble.
How many fewer than 100?
Probability of both/all events occurring is found by multiplying the probabilities of the individual events.
2/5 = .40 for blue marble
?? for green marble.
How many fewer than 100?
Probability of both/all events occurring is found by multiplying the probabilities of the individual events.
Answered by
chocolateman
thanks!
Answered by
unknown
Say there are 65 marbles in the bag. Then there will be 15 red marbles, 26 blue marbles, and 24 green marbles. so without replacement the probability of receiving a green marble and then a red marble would be (24/65)(15/64) which is 9/104
Answered by
kim
probability of choosing a red marble is 1/5 also white marble is 3/10 what is the blue marble probability?
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