Question

a diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 degrees celcius. What is the volume of the bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27 degrees celcius

Answers

(P1V1/T1)= (P2V2/T2)
T must be in kelvin.
580 mL
(P1*V1/T1) = (P2*V2/T2)
(T2*P1*V1/P2*T1) = V2
15+273=288 27+273=300
(300*2.4*250/1*288) = 625mL round to 630mL
answer 630mL
625 mL= round to 630 mL

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