Question

determine the qudratic function whose vertex is (2,-4) and passes through
(3,-1)
fx=

Answer 1

since we know the vertex, let it be

y = a(x-2)^2 - 4
but (3,-1) lies on it
-1 = a(1) - 4
a = 3

y = 3(x-2)^2 - 4

Answer 2

new question using the square to descibe the graph of fx= -8 -16x-x^2