since we know the vertex, let it be
y = a(x-2)^2 - 4
but (3,-1) lies on it
-1 = a(1) - 4
a = 3
y = 3(x-2)^2 - 4
determine the qudratic function whose vertex is (2,-4) and passes through
(3,-1)
fx=
2 answers
new question using the square to descibe the graph of fx= -8 -16x-x^2