Asked by Kim
If 32.6 g of aluminum is produced, how many moles of aluminum nitrate is reacted?
Answers
Answered by
DrBob222
Al(NO3)3 ==> Al not balanced
mols Al = 32.6/atomic mass Al = ?
1 mol Al = 1 mol Al(NO3)3
mols Al = 32.6/atomic mass Al = ?
1 mol Al = 1 mol Al(NO3)3
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