Asked by Luke

7 grams of chloride was dissolved in water. 20 ml of lead(II)nitrate was used to completely precipitate all chloride (assume atomic mass of 35g/mol). What is the molarity of the Lead(II) Nitrate solution.
Answered by DrBob222
2Cl^- + Pb^2+ ==> PbCl2

mols Cl^- = grams/atomic mass Cl.
mols PbCl2 = 1/2 that.
mols Pb^2+ = mol PbCl2.
mols Pb(NO3)2 = mols PbCl2.
M Pb(NO3)2 = mols Pb(NO3)2/L soln.
Answered by Luke
DrBob222, Is the answer 5M?
Answered by DrBob222
Yes
Answered by Luke
thank you
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