Find one numerical value for

Question

cot x/cos x = 5

Answer 1

cotx = 5cosx
cosx/sinx - 5cosx = 0
cosx(1/sinx - 5) = 0
cosx = 0 or 1/sinx = 5

if cosx = 0, x = π/2 , 3π/2

if 1/sinx = 5
sinx = 1/5
x = .20136 or 2.94023