Asked by TRIG HELP
Find one numerical value for
cot x/cos x = 5
cot x/cos x = 5
Answers
Answered by
Reiny
cotx = 5cosx
cosx/sinx - 5cosx = 0
cosx(1/sinx - 5) = 0
cosx = 0 or 1/sinx = 5
if cosx = 0, x = π/2 , 3π/2
if 1/sinx = 5
sinx = 1/5
x = .20136 or 2.94023
cosx/sinx - 5cosx = 0
cosx(1/sinx - 5) = 0
cosx = 0 or 1/sinx = 5
if cosx = 0, x = π/2 , 3π/2
if 1/sinx = 5
sinx = 1/5
x = .20136 or 2.94023
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