Asked by kaitlyn
A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was being driven at 45mi/hr and the rider walks at a speed of 6mi/hr. Teh distance from home to work is 25 miles and the total time for the trip was 2 hours. How far did the motorcycle go before it broke down?
Answers
Answered by
Steve
If the distance on bike was m, then the distance on foot was 25-m.
time = distance/speed.
Add up the times:
m/45 + (25-m)/6 = 2
m=15
check:
15 mi at 45mph = 1/3 hr
10 mi at 6 mph = 5/3 hr
total: 2 hr
time = distance/speed.
Add up the times:
m/45 + (25-m)/6 = 2
m=15
check:
15 mi at 45mph = 1/3 hr
10 mi at 6 mph = 5/3 hr
total: 2 hr
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