Asked by Anonymous

A 9.0 kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 12.0 m/s, determine (a) the translational kinetic energy of its center of gravity.
Answered by bobpursley
a translational=1/2 m v^2

b. rotational: I w^2=I (v^2/r)
where I= lookup. Is it a solid cylinder, or hollow?
Answered by derp
how do you get the radius though?
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