Asked by Emma
0.115 kg of water at 81.0o C is poured into an insulated cup containing 0.220 kg of ice initally at 0o. Calculate the mass of liquid when the system reaches thermal equilibrium.
Answers
Answered by
drwls
In this case, not all of the ice melts. Let m be the number of grams of ice that melts.
115*81*1.0 = m*80
(80 cal/g is the heat of fusion)
m = 116 g
Note that is less than the amount of ice you started out with. So there is some ice left.
Add that to the 115 g of liquid water you had at the beginning.
115*81*1.0 = m*80
(80 cal/g is the heat of fusion)
m = 116 g
Note that is less than the amount of ice you started out with. So there is some ice left.
Add that to the 115 g of liquid water you had at the beginning.
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