Asked by Anonymous
f(x) = 9^x*log_{4}x
f'(x)=?
f'(x)=?
Answers
Answered by
Steve
f = 9^x log<sub>4</sub>x
f' = ln9 9^x + 1/(x ln4)
because log<sub>4</sub>x = lnx/ln4
f' = ln9 9^x + 1/(x ln4)
because log<sub>4</sub>x = lnx/ln4
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