Asked by Anonymous
∫(integral) from 3 to 6 of [(x^3 + 5)/x] dx =?
Answers
Answered by
Steve
come on, man. divide by x and you have
integral[3,6] x^2 + 5/x dx
= 1/3 x^3 + 5 lnx [3,6]
= 63 + ln32
integral[3,6] x^2 + 5/x dx
= 1/3 x^3 + 5 lnx [3,6]
= 63 + ln32
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