Asked by Leslie
In a Bohr of a Hydrogen atom, an electron moves in a circle with a radius of 5.10(^-9) cm around a nucleus charged positive due to electrostatic force. What is the intensity of the force so that the electron has a velocity of 2.3 x 10(^8) cm/s? The mass of the electron is 9x10(^-28)g.
I tried to break this problem down into components using F=ma and a=vt, but I could get nowhere. Thank you to anyone who could break down the steps and help!
I tried to break this problem down into components using F=ma and a=vt, but I could get nowhere. Thank you to anyone who could break down the steps and help!
Answers
Answered by
Elena
F=ma=mv²/R =
=9.1•10⁻³¹• (2.3•10⁶ )²/ 5.1•10⁻¹¹=
=9.45•10⁻⁸ N
=9.1•10⁻³¹• (2.3•10⁶ )²/ 5.1•10⁻¹¹=
=9.45•10⁻⁸ N
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.