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Consider a pulse of laser light aimed at the Moon that bounces back to Earth. The distance between Earth and the Moon is 3.84 *...Asked by Shawn
Consider a pulse of laser light aimed at the Moon that
bounces back to Earth. The distance between Earth and
the Moon is 3.84 * 108 m. Show that the round-trip
time for the light is 2.56 s
bounces back to Earth. The distance between Earth and
the Moon is 3.84 * 108 m. Show that the round-trip
time for the light is 2.56 s
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Answered by
Shawn=Help please
During a solar eclipse, the moon (of mass 7.36 × 1022 kg), Earth (of mass 5.98 × 1024 kg), and Sun (of mass 1.99 × 1030 kg) lie on the same line, with the moon between Earth and the Sun.
1.What gravitational force is exerted on the moon by the Sun? The universal gravitational constant is 6.673 × 10-11 N · m2/kg2,the Earth-moon distance is 3.84 × 108 m, and the Earth-Sun distance is 1.496 × 1011 m.
Answer in units of N.
2.What gravitational force is exerted on the moon by Earth?Answer in units of N.
3.What gravitational force is exerted on Earth by the Sun? Answer in units of N.
1.What gravitational force is exerted on the moon by the Sun? The universal gravitational constant is 6.673 × 10-11 N · m2/kg2,the Earth-moon distance is 3.84 × 108 m, and the Earth-Sun distance is 1.496 × 1011 m.
Answer in units of N.
2.What gravitational force is exerted on the moon by Earth?Answer in units of N.
3.What gravitational force is exerted on Earth by the Sun? Answer in units of N.
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