Asked by Britney
Find the relative extrema, if any, of the function. Use the second derivative test, if applicable.
g(x)=4x^2+7x+6
relative maximum
(x, y) = (, )
relative minimum
(x, y) = (, )
g(x)=4x^2+7x+6
relative maximum
(x, y) = (, )
relative minimum
(x, y) = (, )
Answers
Answered by
Reiny
your curve is a parabola opening upwards, so there is only one minimum and no maximum196/64 + 7(
g ' (x) = 8x + 7
= 0
8x = -7
x=-7/8
g(-7/8) = 196/64 - 49/8 + 6
= 47/16
minimum or vertex is (-7/8 , 47/16)
g ' (x) = 8x + 7
= 0
8x = -7
x=-7/8
g(-7/8) = 196/64 - 49/8 + 6
= 47/16
minimum or vertex is (-7/8 , 47/16)
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