Asked by JESS
1)how do you simplify 3xcos5x using trigometric functions
2)how do you simplify sin2xcos4x using trigometric functions
2)how do you simplify sin2xcos4x using trigometric functions
Answers
Answered by
Steve
don't know what you mean by "simplify". They're already pretty simple.
I see no way to rewrite 3x cos5x
sin2x cos4x = (sin6x + sin2x)/2
but that doesn't look any simpler to me.
any further clarification?
I see no way to rewrite 3x cos5x
sin2x cos4x = (sin6x + sin2x)/2
but that doesn't look any simpler to me.
any further clarification?
Answered by
JESS
how did you do sin2x cos4x = (sin6x + sin2x)/2 what os the formula I need to use
Answered by
JESS
Steve help please
Answered by
Steve
use the trig sum-to-difference formulas
sinAcosB = (sin(A+B) + sin(A-B))/2
You must have seen such. If not a visit to
http://oakroadsystems.com/twt/sumdiff.htm
bears study
sinAcosB = (sin(A+B) + sin(A-B))/2
You must have seen such. If not a visit to
http://oakroadsystems.com/twt/sumdiff.htm
bears study
Answered by
JESS
cos3xcos5x
how do rewrie this using trigmetric finctions Steve thanks
how do rewrie this using trigmetric finctions Steve thanks
Answered by
Steve
come on - give it a try using the formulas. What do you come up with?
Answered by
JESS
(cos8x+cos2x)/2 steve is it right
Answered by
JESS
steve
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