Question
If a firm has the following cost anfd revenue functions find the break even points
C(x)=3600+25x+1/2x^2
R(x)=(175-1/2x)x
C(x)=3600+25x+1/2x^2
R(x)=(175-1/2x)x
Answers
Damon
I hope you mean:
C(x)=3600+25x+(1/2)x^2
R(x)=(175-(1/2)x)x
where does C = R?
.5 x^2 + 25 x +3600 = 175 x - .5 x^2
x^2 -150 x + 3600 = 0
(x-120)(x-30) = 0
x = 120 or x = 30
C(x)=3600+25x+(1/2)x^2
R(x)=(175-(1/2)x)x
where does C = R?
.5 x^2 + 25 x +3600 = 175 x - .5 x^2
x^2 -150 x + 3600 = 0
(x-120)(x-30) = 0
x = 120 or x = 30