I have a 4" hose attached to a 2" nozzle, me resistance coeffient of the nozzle is .12, and the jet of water exiting the nozzle is 24.4 m/sec. The water is flowing from the 4" to the 2". What I am having trouble finding is Pressure 1 and the the velocity 1.
What I know is that P2=0, areas of the hose is 4" = 12.56 in^2 converts to .008m^2, 2" = 3.14 in^2 converts to .002m^2, I think Q=V2*A2 = 24.4*.002= .049 m^3/sec
then v1= 6.125 m/s?
then would I plug this into the bernoulli's equ.??
Thank You
Yes, plug it into Bernoulli's equation.
On the continuity equation, you didn't need to do all that converting...The area of the larger is four times the smaller, so
V1A1=V2A2
V1*4=24.4 m/sec
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