a particle is moving counterclockwise around the circular path whose equation is x^2+y^2=100 of the abscissa of the particle is increasing by 72in/sec at a point where x=8 find the rate of changeof the cordinate(y) at this point

Question

a particle is moving counterclockwise around the circular path whose equation is x^2+y^2=100 of the abscissa of the particle is increasing by 72in/sec at a point where  x=8 find the rate of changeof the cordinate(y) at this point

Steve · Accepted Answer

the rate of ordinate change is dy/dt. x^2 + y^2 = 100 2x dx/dt + 2y dy/dt = 0 when x=8, y=6, so 2(8)(72) + 2(6) dy/dt = 0 12 dy/dt = -1152 dy/dt = -96 in/s