Asked by Molly
If sandy and Betty have 192 toys in all and Sandygive Betty 50 toys so know sandy has three times as much as betty
Answers
Answered by
Steve
mumble mumble
s-50 = 3(b+50)
but s = 192-b, so
192-b - 50 = 3b + 150
4b = -8
b = -2
eh? Negative toys? Maybe it's the other way around: betty has 3 times as much as sandy
3(s-50) = b+50
3s - 150 = 192-s+50
4s = 392
s = 98
so, if sandy has 98 and betty has 84,
after sandy gives betty 50,
sandy has 48 and betty has 134 = 3x48
s-50 = 3(b+50)
but s = 192-b, so
192-b - 50 = 3b + 150
4b = -8
b = -2
eh? Negative toys? Maybe it's the other way around: betty has 3 times as much as sandy
3(s-50) = b+50
3s - 150 = 192-s+50
4s = 392
s = 98
so, if sandy has 98 and betty has 84,
after sandy gives betty 50,
sandy has 48 and betty has 134 = 3x48
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