Question
If sandy and Betty have 192 toys in all and Sandygive Betty 50 toys so know sandy has three times as much as betty
Answers
Steve
mumble mumble
s-50 = 3(b+50)
but s = 192-b, so
192-b - 50 = 3b + 150
4b = -8
b = -2
eh? Negative toys? Maybe it's the other way around: betty has 3 times as much as sandy
3(s-50) = b+50
3s - 150 = 192-s+50
4s = 392
s = 98
so, if sandy has 98 and betty has 84,
after sandy gives betty 50,
sandy has 48 and betty has 134 = 3x48
s-50 = 3(b+50)
but s = 192-b, so
192-b - 50 = 3b + 150
4b = -8
b = -2
eh? Negative toys? Maybe it's the other way around: betty has 3 times as much as sandy
3(s-50) = b+50
3s - 150 = 192-s+50
4s = 392
s = 98
so, if sandy has 98 and betty has 84,
after sandy gives betty 50,
sandy has 48 and betty has 134 = 3x48