Question

A boy shoves his stuffed toy zebra down a friction-less chute, starting at a height of 1.07 m above the bottom of the chute and with an initial speed of 1.87 m/s. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with coefficient of kinetic friction 0.277. How far from the bottom of the chute does the toy zebra come to rest? Take g = 9.81 m/s2.

Hint: How does the work performed on the toy by the force of friction relate to the requested distance? How do the initial height and speed relate to the frictional work?

Answer 1

Energy conservation tells you that

M*g*H + M*Vo^2/2 = (mu)*M*g*X

Mass M cancels out. Solve for slide distance X.

mu = 0.277
g = 9.81 m/s^2
Vo = 1.87 m/s

Answer 2

Thank you so much!!! this really helped!!!

Answer 3

H = 1.07;
k = 0.277
g = 9.81 m/s^2
Vo = 1.87 m/s

we know, M*g*H + M*Vo^2/2 = k*M*g*X

So, x = (g*H + (Vo)^2/2) / (mu * g)