Asked by Anonymous
You are using Newton's method to solve x^3-5x-2=0. If your first guess is X1=2, what value will you calculate for the next approximation X2?
Answers
Answered by
Reiny
your equation would be
x<sub>new</sub> = x - (x^3 - 5x - 2)/(3x^2 - 5)
so for x=2
x<sub>new</sub> = 2 - (8-10-2)/(12-5)
= 2.5714
Incidentally, my next 4 answers were
2.4268029
2.4143045
2.4142136 and
2.4142136 which would be one of the answers correct up to 7 decimal places.
x<sub>new</sub> = x - (x^3 - 5x - 2)/(3x^2 - 5)
so for x=2
x<sub>new</sub> = 2 - (8-10-2)/(12-5)
= 2.5714
Incidentally, my next 4 answers were
2.4268029
2.4143045
2.4142136 and
2.4142136 which would be one of the answers correct up to 7 decimal places.
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