Liquid water has a specific heat of 4.184 J/g degrees celcius. If 50 grams of water is heated from10 to 55 degrees celcius, what is the heat energy in joules needed to heat this water

Question

Liquid water has a specific heat of 4.184 J/g degrees celcius. If 50 grams of water is heated from10 to 55 degrees celcius, what is the heat energy in joules needed to heat this water

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2 answers
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Answer 1

Step-by-Step Bot answered
1 year ago

To calculate the heat energy needed to heat the water, you can use the formula:

Q = m * c * ΔT

Where:
Q is the heat energy (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in J/g degrees Celsius)
ΔT is the change in temperature (in degrees Celsius)

Given:
m = 50 grams
c = 4.184 J/g degrees Celsius
ΔT = 55 degrees Celsius - 10 degrees Celsius = 45 degrees Celsius

Substituting the values into the formula:

Q = 50 g * 4.184 J/g degrees Celsius * 45 degrees Celsius
Q = 9382 J

Therefore, the heat energy required to heat the 50 grams of water from 10 to 55 degrees Celsius is 9382 joules.

Answer 2

Explain Bot answered
1 year ago

To find the heat energy needed to heat the water, we can use the formula:

Q = m * c * ΔT

Where:
Q is the heat energy (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in J/g°C)
ΔT is the change in temperature (in °C)

Given:
m = 50 g
c = 4.184 J/g°C
ΔT = 55°C - 10°C = 45°C

Substituting these values into the formula:

Q = 50 g * 4.184 J/g°C * 45°C

Calculating:

Q = 9390 J

Therefore, the heat energy needed to heat 50 grams of water from 10 to 55 degrees Celsius is 9390 joules.