Asked by mohammed

Calculate the number of grams of calcium chloride (CaCl2) needed to react with excess silver nitrate (AgNO3) to produce 6.60 g of silver chloride (AgCl). The equation for the reaction is given below:
CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2

12 years ago

Answered by Steve

6.6g AgCl = .046 moles

each mole CaCl2 yields 2 moles AgCl, so only 0.023 moles CaCl2 are needed.

.023 moles CaCl2 = 2.55g

12 years ago

Answered by Dharm Raj

Verify karke samghe

6 years ago

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