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At 860.0 deg celsius, the equilibrium constant Kp for the synthesis of ammonia (below) is 3.35 * 10^-5. What is the value of Kc?

N2(g) + 3H2(g) <--> 2NH3(g)
12 years ago

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Answered by DrBob222
Kp = Kc(RT)^delta n
where delta n = nproducts-nreacrtants.
12 years ago
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At 860.0 deg celsius, the equilibrium constant Kp for the synthesis of ammonia (below) is 3.35 * 10^-5. What is the value of Kc?

N2(g) + 3H2(g) <--> 2NH3(g)

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