Asked by kourtney

Au^3+ + 3e^- ---> Au

Is this oxidation or reduction?

Which reactant has been oxidized?
Au3+ (aq)+ 3Na(s)--->3Na^+(aq)+Au(s)

2.Which reactant has been reduced

3.What is the reducing agent?

4.what is the oxidizing agent?

I am having a hard time understanding how to do these. If you could be so kind as to help me I would love it! Thanks heads up!!!
Answered by Sanya
The first rxn is reduction. Au went from +3 to 0 so higher to lower number (became more -ve)
Na is oxidized. went form 0 to +3
Answered by Kourt(Question)
Is the Na one the anwser to number 1 and (went from 0 to +3) number 3? Whats number 4? Thanks
Answered by Sanya
What is your charge for Au? There has to be a positive and negative- check your equations- that answers then may not apply.
Answered by Sanya
Positive and negative- in the sense things should cancel and charges should inc. and dec.
Answered by DrBob222
#4. Ths oxidizing agent is the substance reduced. The reducing agent is the substance oxidized.
Na is the reducing agent and it is oxidized.
Au^3+ is the oxidizing agent and it is reduced.
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