The torque is M=F•cosα•L.
The ball is material point => its moment of inertia is
I=m•L².
The Newton’s 2 law for rotation
M=I•ε,
F•cosα•L= m•L²•ε,
ε= F•cosα•L/ m•L²=F•cosα /m•L.
A ball of mass 0.1 kg is suspended vertically from the ceiling with a "massless" string and
brought to rest. The string is one meter long. When a force of 0.5N is applied 45 deg. below
the horizontal, what will be the magnitude of the resulting angular acceleration of the ball?
How would you go about solving this?
1 answer
1 answer