Asked by Joe
A paperweight weighs 6.9N in air. When it is completely submerged in water it appears to weigh 4.3N. A) What is the volume of the paperweight? B) What is the density paperweight? The density of water is 1000kg/m3.
Answers
Answered by
Henry
Fb = 6.9 - 4.3 = 2.6 N. =Buoyancy force
= Wt. of water displaced.
m*g = 2.6 N.
m = 2.6/g = 2.6/9.8 = 0.2653 kg. = Mass
of water displaced.
A. Vp = Vw = mass/Dw=0.2653/1000kg/m^3=
2.653*10^-4 m^3 = Vol. of paperweight =
Vol. of water.
B. m*g = 6.9 N.
m = 6.9/g = 6.9/9.8 = 0.7041 kg.
Density = m/V = 0.7041/2.653*10^-4 =
2654 kg/M^3.
= Wt. of water displaced.
m*g = 2.6 N.
m = 2.6/g = 2.6/9.8 = 0.2653 kg. = Mass
of water displaced.
A. Vp = Vw = mass/Dw=0.2653/1000kg/m^3=
2.653*10^-4 m^3 = Vol. of paperweight =
Vol. of water.
B. m*g = 6.9 N.
m = 6.9/g = 6.9/9.8 = 0.7041 kg.
Density = m/V = 0.7041/2.653*10^-4 =
2654 kg/M^3.
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