To determine how high the temperature of the block of glass will rise, we can use the formula for heat transfer:
\[ Q = mc\Delta T \]
Where:
- \( Q \) is the amount of heat added (in joules),
- \( m \) is the mass of the substance (in kg),
- \( c \) is the specific heat capacity (in J/kg·K),
- \( \Delta T \) is the change in temperature (in K).
Given:
- \( Q = 800 \) J,
- \( m = 0.3 \) kg,
- \( c = 664 \) J/kg·K.
We need to find \( \Delta T \):
- Rearranging the formula to solve for \( \Delta T \):
\[ \Delta T = \frac{Q}{mc} \]
- Substituting in the known values:
\[ \Delta T = \frac{800 , \text{J}}{0.3 , \text{kg} \times 664 , \text{J/kg·K}} \]
- Calculating the denominator:
\[ 0.3 , \text{kg} \times 664 , \text{J/kg·K} = 199.2 , \text{J/K} \]
- Now substitute the result back into the equation for \( \Delta T \):
\[ \Delta T = \frac{800 , \text{J}}{199.2 , \text{J/K}} \approx 4.01 , \text{K} \]
- Finally, to find the new temperature of the glass:
\[ \text{Final Temperature} = \text{Initial Temperature} + \Delta T \] \[ \text{Final Temperature} = 300 , \text{K} + 4.01 , \text{K} \approx 304.01 , \text{K} \]
Thus, the temperature of the glass will rise approximately to 304.01 K.