80% of the American population likes pizza. If 8 Americans are chosen at random, find the probability that 6 of them like pizza.

Answer 1

n=8, p=.80, q=1-.80=0.20, x=6

P(x)=nCxPxQn-x

P(x)=8C6(0.80)6(0.20)2

= (28)x(0.262144)x(0.04)

=0.294