80.0 ml of 1.50 M lead (IV) acetate is added to a 65.5 ml solution of 1.25 potassium chloride. 5.84 grams precipitate are collected. what is the percent yield? Calculate the concentrations of all ions remaining in solution.
Okay so I know you have to convert to moles of each compound, but I'm really not sure of anything else or how to even set the problem up....
1 answer
Check your post. Are you sure that is lead(IV) acetate and not lead(II) acetate. The ppt will be lead(II) chloride, PbCl2, and not PbCl4.