8. Solve each of the following trigonometric equations and find all solutions in the interval: 0<= θ <=2pi
f. 2sin^2 x - x - 1 = 0
3 answers
I made the wrong title, I need help solving this equation.
2sin^2 x - x - 1 = 0 Hmmmm. Are you certain you copied it correctly, there is a very famous similar problem that can be solved: 2sin^2x - sin x -1=0
I dont know how else to type it, maybe this way?
Interval: 0<= θ <=2pi
(2sin^2) x - x - 1 = 0
Interval: 0<= θ <=2pi
(2sin^2) x - x - 1 = 0
1 answer