To find the cat's total displacement, we need to calculate the net distance and direction of its movement. To do this, we can add up the distances moved in each direction:
Total displacement = (3.5 m east) + (-4.2 m west) + (-1.2 m west) + (6.6 m east)
= 3.5 m - 4.2 m - 1.2 m + 6.6 m
= 4.7 m
Therefore, the cat's total displacement is 4.7 meters to the east.
To find the cat's total distance, we simply add up the absolute values of the distances moved in each direction:
Total distance = |3.5 m| + |-4.2 m| + |-1.2 m| + |6.6 m|
= 3.5 m + 4.2 m + 1.2 m + 6.6 m
= 15.5 m
Therefore, the cat's total distance traveled is 15.5 meters.
The average velocity is the total displacement divided by the total time elapsed:
Average velocity = Total displacement / Total time
= 4.7 m / 2 s
= 2.35 m/s
Therefore, the cat's average velocity is 2.35 meters per second.
The average speed is the total distance divided by the total time elapsed:
Average speed = Total distance / Total time
= 15.5 m / 2 s
= 7.75 m/s
Therefore, the cat's average speed is 7.75 meters per second.
8. A nervous cat, trying to cross a road, first moved 3.5 m east, then 4.2 m west, then 1.2 m
west, then 6.6 m east. What is the cat's
a) total displacement?
b) total distance?
c) average velocity if the total time elapsed is 2 s.
d) average speed if the total time elapsed is 2 s.
1 answer
1 answer