To determine the percentage of offspring that will have round and yellow seeds from the cross of homozygous plants \(RRYY\) and \(rryy\), we need to analyze the genotypes of the parents and the potential offspring.
- Parent 1 (RRYY) produces gametes: RY
- Parent 2 (rryy) produces gametes: ry
When we perform the cross:
\[
\text{Gametes from Parent 1: } RY
\text{Gametes from Parent 2: } ry
\]
The resulting genotype from this cross will be:
\[ \text{F1 Generation: } RrYy \]
Now, we will analyze the phenotype of the F1 generation:
- The dominant allele \(R\) (for round seeds) will mask the recessive allele \(r\) (for wrinkled seeds).
- The dominant allele \(Y\) (for yellow seeds) will mask the recessive allele \(y\) (for green seeds).
Since all offspring will have the genotype \(RrYy\), they will all exhibit the dominant traits: round seeds and yellow seeds.
Thus, 100% of the offspring will have round and yellow seeds.
The correct answer is 100%.
1 answer