8.10-L container holds a mixture of two gases at 45 °C. The partial pressures of gas A and gas B, respectively, are 0.153 atm and 0.882 atm. If 0.110 mol a third gas is added with no change in volume or temperature, what will the total pressure become?

Answer 1

the partial pressure of the third gas will be

P=nRT/V solve that, then add it to the sum of the first two pressures.

Answer 2

Dinah, I worked one JUST LIKE this yesterday for you (both the short way and the long way). You should be able to see the connection and not ask for help when it's the same type problem.