8.00 gram of calcium chloride. Is dissolved in 1.000kg of Water. How many moles of calcium chloride are in solution? How many moons of water? Are present.

Answer 1

To calculate the number of moles of calcium chloride, we need to use its molar mass. The molar mass of calcium chloride is:

CaCl2 = 1 x 40.08 g/mol (for calcium) + 2 x 35.45 g/mol (for chlorine) = 110.98 g/mol

So, the number of moles of calcium chloride in 8.00 g is:

n = m/M = 8.00 g /110.98 g/mol = 0.072 mol

To calculate the number of moles of water, we can use its molar mass, which is:

H2O = 2 x 1.01 g/mol (for hydrogen) + 1 x 16.00 g/mol (for oxygen) = 18.02 g/mol

The mass of 1.000 kg of water is:

m = 1.000 kg x 1000 g/kg = 1000 g

So, the number of moles of water is:

n = m/M = 1000 g / 18.02 g/mol = 55.49 mol

Therefore, there are 0.072 moles of calcium chloride and 55.49 moles of water present in the solution.