To find the product of these two binomials, we need to distribute each term of the first binomial to each term of the second binomial.
(7y + 2)(y^2 + 8y + 6)
= 7y(y^2) + 7y(8y) + 7y(6) + 2(y^2) + 2(8y) + 2(6)
= 7y^3 + 56y^2 + 42y + 2y^2 + 16y + 12
= 7y^3 + 58y^2 + 58y + 12
So, the product is 7y^3 + 58y^2 + 58y + 12.
(7y+2)(y^2+8y+6)
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