The first equation, 7x+3=7x+3 is an identity, meaning that it's true for any value of x. To see this, we can simplify the equation by subtracting 7x from both sides:
7x+3-7x = 7x+3-7x
3 = 3
Since 3 is always equal to 3, the equation is true regardless of the value of x. So, this equation has infinitely many solutions.
The second equation, 3(4x+8)=4(3x+6), can be simplified by distributing the multiplication on both sides:
12x + 24 = 12x + 24
Again, we have an identity, where both sides of the equation are equal to each other regardless of the value of x. This means that this equation also has infinitely many solutions.
In both cases, we can see that the equation can have more than one solution because we end up with an identity that is always true for any value of x.
7x+3=7x+3 3(4x+8)=4(3x6)
the original equations and check to show that the equations can have more than one solution. Explain your work.
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